|
正常编译,在新建action中无法列出我写的方法。
请问我该如何调用,谢谢
代码如下:
- public class Account {
- public static JSONObject userLogin(JSONObject params, ActionContext context) throws SQLException, NamingException, java.sql.SQLException {
-
- /*String startDate = params.getString("startDate");
- String endDate = params.getString("endDate");*/
-
- String code =params.getString("Code");
- String phone =params.getString("Name");
- String password=params.getString("LoginPwd");
-
- List<Object> sqlParams = new ArrayList<Object>();
- sqlParams.add(code);
- sqlParams.add(phone);
- sqlParams.add(password);
-
-
- Table table = null;
- Connection conn = context.getConnection("CloudCulture");
- String sql = "";
- try{
- if(code != null && password!=null){
- sql = "SELECT ID,CODE,NAME,GENDER,PHONE,EMAIL FROM SYS_USER WHERE CODE=? AND LOGINPWD=? ";
-
- table = DataUtils.queryData(conn, sql, sqlParams, null, null, null);
- }
- else if (phone!=null && password!=null){
- sql = "SELECT ID,CODE,NAME,GENDER,PHONE,EMAIL FROM SYS_USER WHERE PHONE=? AND LOGINPWD=? ";
-
- table = DataUtils.queryData(conn, sql, sqlParams, null, null, null);
- }
- else{
- sql = "SELECT ID,CODE,NAME,GENDER,PHONE,EMAIL FROM SYS_USER ";
-
- table = DataUtils.queryData(conn, sql, null, null, null, null);
- }
-
-
- return Transform.tableToJson(table);
-
- } finally {
- conn.close();
- }
-
-
- }
- }
复制代码 |
|